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280=4(10+5)+2(5+h)
We move all terms to the left:
280-(4(10+5)+2(5+h))=0
We add all the numbers together, and all the variables
-(415+2(h+5))+280=0
We calculate terms in parentheses: -(415+2(h+5)), so:We get rid of parentheses
415+2(h+5)
determiningTheFunctionDomain 2(h+5)+415
We multiply parentheses
2h+10+415
We add all the numbers together, and all the variables
2h+425
Back to the equation:
-(2h+425)
-2h-425+280=0
We add all the numbers together, and all the variables
-2h-145=0
We move all terms containing h to the left, all other terms to the right
-2h=145
h=145/-2
h=-72+1/2
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