280=4(10+5)+2(5+h)

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Solution for 280=4(10+5)+2(5+h) equation: 



280=4(10+5)+2(5+h)

We move all terms to the left:

280-(4(10+5)+2(5+h))=0

We add all the numbers together, and all the variables

-(415+2(h+5))+280=0



We calculate terms in parentheses: -(415+2(h+5)), so:

415+2(h+5)

determiningTheFunctionDomain
2(h+5)+415

We multiply parentheses

2h+10+415

We add all the numbers together, and all the variables

2h+425

Back to the equation:

-(2h+425)



We get rid of parentheses

-2h-425+280=0

We add all the numbers together, and all the variables

-2h-145=0

We move all terms containing h to the left, all other terms to the right

-2h=145

h=145/-2

h=-72+1/2

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