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280x^2-2564.12x-66.91=0
a = 280; b = -2564.12; c = -66.91;
Δ = b2-4ac
Δ = -2564.122-4·280·(-66.91)
Δ = 6649650.5744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2564.12)-\sqrt{6649650.5744}}{2*280}=\frac{2564.12-\sqrt{6649650.5744}}{560} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2564.12)+\sqrt{6649650.5744}}{2*280}=\frac{2564.12+\sqrt{6649650.5744}}{560} $
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