281=7(8y-3)+2(6+y)

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Solution for 281=7(8y-3)+2(6+y) equation: 



281=7(8y-3)+2(6+y)

We move all terms to the left:

281-(7(8y-3)+2(6+y))=0

We add all the numbers together, and all the variables

-(7(8y-3)+2(y+6))+281=0



We calculate terms in parentheses: -(7(8y-3)+2(y+6)), so:

7(8y-3)+2(y+6)

We multiply parentheses

56y+2y-21+12

We add all the numbers together, and all the variables

58y-9

Back to the equation:

-(58y-9)



We get rid of parentheses

-58y+9+281=0

We add all the numbers together, and all the variables

-58y+290=0

We move all terms containing y to the left, all other terms to the right

-58y=-290

y=-290/-58

y=+5

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