282=(x)+(5/x)+(x-15)

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Solution for 282=(x)+(5/x)+(x-15) equation: 



282=(x)+(5/x)+(x-15)

We move all terms to the left:

282-((x)+(5/x)+(x-15))=0



Domain of the equation: x)+(x-15))!=0

x∈R



We add all the numbers together, and all the variables

-(x+(+5/x)+(x-15))+282=0

We multiply all the terms by the denominator


-(x+(+5+282*x)+(x-15))=0



We calculate terms in parentheses: -(x+(+5+282*x)+(x-15)), so:

x+(+5+282*x)+(x-15)

We add all the numbers together, and all the variables

x+(282x+5)+(x-15)

We get rid of parentheses

x+282x+x+5-15

We add all the numbers together, and all the variables

284x-10

Back to the equation:

-(284x-10)



We get rid of parentheses

-284x+10=0

We move all terms containing x to the left, all other terms to the right

-284x=-10

x=-10/-284

x=5/142

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