282=x+(x/5)+(x+15)

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Solution for 282=x+(x/5)+(x+15) equation: 



282=x+(x/5)+(x+15)

We move all terms to the left:

282-(x+(x/5)+(x+15))=0



Domain of the equation: 5)+(x+15))!=0

x∈R



We add all the numbers together, and all the variables

-(x+(+x/5)+(x+15))+282=0

We multiply all the terms by the denominator


-(x+(+x+282*5)+(x+15))=0



We calculate terms in parentheses: -(x+(+x+282*5)+(x+15)), so:

x+(+x+282*5)+(x+15)

We add all the numbers together, and all the variables

x+(x+1410)+(x+15)

We get rid of parentheses

x+x+x+1410+15

We add all the numbers together, and all the variables

3x+1425

Back to the equation:

-(3x+1425)



We get rid of parentheses

-3x-1425=0

We move all terms containing x to the left, all other terms to the right

-3x=1425

x=1425/-3

x=-475

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