282=x+x/5+(x-15)

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Solution for 282=x+x/5+(x-15) equation: 



282=x+x/5+(x-15)

We move all terms to the left:

282-(x+x/5+(x-15))=0



Domain of the equation: 5+(x-15))!=0

We move all terms containing x to the left, all other terms to the right

(x-15))!=-5

x∈R



We multiply all the terms by the denominator


-(x+x+282*5+(x-15))=0



We calculate terms in parentheses: -(x+x+282*5+(x-15)), so:

x+x+282*5+(x-15)

determiningTheFunctionDomain
x+x+(x-15)+282*5

We add all the numbers together, and all the variables

2x+(x-15)+1410

We get rid of parentheses

2x+x-15+1410

We add all the numbers together, and all the variables

3x+1395

Back to the equation:

-(3x+1395)



We get rid of parentheses

-3x-1395=0

We move all terms containing x to the left, all other terms to the right

-3x=1395

x=1395/-3

x=-465

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