288=(x+1)+(x+2)

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Solution for 288=(x+1)+(x+2) equation:



288=(x+1)+(x+2)
We move all terms to the left:
288-((x+1)+(x+2))=0
We calculate terms in parentheses: -((x+1)+(x+2)), so:
(x+1)+(x+2)
We get rid of parentheses
x+x+1+2
We add all the numbers together, and all the variables
2x+3
Back to the equation:
-(2x+3)
We get rid of parentheses
-2x-3+288=0
We add all the numbers together, and all the variables
-2x+285=0
We move all terms containing x to the left, all other terms to the right
-2x=-285
x=-285/-2
x=142+1/2

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