288=20x+2(x)(x)

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Solution for 288=20x+2(x)(x) equation: 



288=20x+2(x)(x)

We move all terms to the left:

288-(20x+2(x)(x))=0

We add all the numbers together, and all the variables

-(+20x+2xx)+288=0

We get rid of parentheses

-20x-2xx+288=0

We move all terms containing x to the left, all other terms to the right

-20x-2xx=-288

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