288=8(6b+1)+8b

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Solution for 288=8(6b+1)+8b equation: 



288=8(6b+1)+8b

We move all terms to the left:

288-(8(6b+1)+8b)=0



We calculate terms in parentheses: -(8(6b+1)+8b), so:

8(6b+1)+8b

We add all the numbers together, and all the variables

8b+8(6b+1)

We multiply parentheses

8b+48b+8

We add all the numbers together, and all the variables

56b+8

Back to the equation:

-(56b+8)



We get rid of parentheses

-56b-8+288=0

We add all the numbers together, and all the variables

-56b+280=0

We move all terms containing b to the left, all other terms to the right

-56b=-280

b=-280/-56

b=+5

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