289+b2=484

Solution for 289+b2=484 equation:

289+b2=484

We move all terms to the left:

289+b2-(484)=0

We add all the numbers together, and all the variables

b^2-195=0

a = 1; b = 0; c = -195;
Δ = b2-4ac
Δ = 02-4·1·(-195)
Δ = 780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{780}=\sqrt{4*195}=\sqrt{4}*\sqrt{195}=2\sqrt{195}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{195}}{2*1}=\frac{0-2\sqrt{195}}{2}
=-\frac{2\sqrt{195}}{2}
=-\sqrt{195}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{195}}{2*1}=\frac{0+2\sqrt{195}}{2}
=\frac{2\sqrt{195}}{2}
=\sqrt{195}
$