289=v2

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Solution for 289=v2 equation:



289=v2
We move all terms to the left:
289-(v2)=0
We add all the numbers together, and all the variables
-1v^2+289=0
a = -1; b = 0; c = +289;
Δ = b2-4ac
Δ = 02-4·(-1)·289
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-34}{2*-1}=\frac{-34}{-2} =+17 $
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+34}{2*-1}=\frac{34}{-2} =-17 $

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