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289x^2=324
We move all terms to the left:
289x^2-(324)=0
a = 289; b = 0; c = -324;
Δ = b2-4ac
Δ = 02-4·289·(-324)
Δ = 374544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{374544}=612$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-612}{2*289}=\frac{-612}{578} =-1+1/17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+612}{2*289}=\frac{612}{578} =1+1/17 $
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