28=(7y-4)+(y+5)

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Solution for 28=(7y-4)+(y+5) equation:



28=(7y-4)+(y+5)
We move all terms to the left:
28-((7y-4)+(y+5))=0
We calculate terms in parentheses: -((7y-4)+(y+5)), so:
(7y-4)+(y+5)
We get rid of parentheses
7y+y-4+5
We add all the numbers together, and all the variables
8y+1
Back to the equation:
-(8y+1)
We get rid of parentheses
-8y-1+28=0
We add all the numbers together, and all the variables
-8y+27=0
We move all terms containing y to the left, all other terms to the right
-8y=-27
y=-27/-8
y=3+3/8

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