28=-2(m+1)-6(m-5)+8m

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Solution for 28=-2(m+1)-6(m-5)+8m equation: 



28=-2(m+1)-6(m-5)+8m

We move all terms to the left:

28-(-2(m+1)-6(m-5)+8m)=0



We calculate terms in parentheses: -(-2(m+1)-6(m-5)+8m), so:

-2(m+1)-6(m-5)+8m

We add all the numbers together, and all the variables

8m-2(m+1)-6(m-5)

We multiply parentheses

8m-2m-6m-2+30

We add all the numbers together, and all the variables

28

Back to the equation:

-(28)



We add all the numbers together, and all the variables

=0

m=0/1

m=0

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