28=-7(2z+4)

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Solution for 28=-7(2z+4) equation: 



28=-7(2z+4)

We move all terms to the left:

28-(-7(2z+4))=0



We calculate terms in parentheses: -(-7(2z+4)), so:

-7(2z+4)

We multiply parentheses

-14z-28

Back to the equation:

-(-14z-28)



We get rid of parentheses

14z+28+28=0

We add all the numbers together, and all the variables

14z+56=0

We move all terms containing z to the left, all other terms to the right

14z=-56

z=-56/14

z=-4

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