28=-7(5z-2)

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Solution for 28=-7(5z-2) equation: 



28=-7(5z-2)

We move all terms to the left:

28-(-7(5z-2))=0



We calculate terms in parentheses: -(-7(5z-2)), so:

-7(5z-2)

We multiply parentheses

-35z+14

Back to the equation:

-(-35z+14)



We get rid of parentheses

35z-14+28=0

We add all the numbers together, and all the variables

35z+14=0

We move all terms containing z to the left, all other terms to the right

35z=-14

z=-14/35

z=-2/5

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