28=-8y+2(y+5)

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Solution for 28=-8y+2(y+5) equation: 



28=-8y+2(y+5)

We move all terms to the left:

28-(-8y+2(y+5))=0



We calculate terms in parentheses: -(-8y+2(y+5)), so:

-8y+2(y+5)

We multiply parentheses

-8y+2y+10

We add all the numbers together, and all the variables

-6y+10

Back to the equation:

-(-6y+10)



We get rid of parentheses

6y-10+28=0

We add all the numbers together, and all the variables

6y+18=0

We move all terms containing y to the left, all other terms to the right

6y=-18

y=-18/6

y=-3

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