28=12+3y

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Solution for 28=12+3y equation:



28=12+3y
We move all terms to the left:
28-(12+3y)=0
We add all the numbers together, and all the variables
-(3y+12)+28=0
We get rid of parentheses
-3y-12+28=0
We add all the numbers together, and all the variables
-3y+16=0
We move all terms containing y to the left, all other terms to the right
-3y=-16
y=-16/-3
y=5+1/3

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