28=1c+11

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Solution for 28=1c+11 equation: 



28=1c+11

We move all terms to the left:

28-(1c+11)=0

We add all the numbers together, and all the variables

-(c+11)+28=0

We get rid of parentheses

-c-11+28=0

We add all the numbers together, and all the variables

-1c+17=0

We move all terms containing c to the left, all other terms to the right

-c=-17

c=-17/-1

c=+17

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