28=2(2x-5+x)

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Solution for 28=2(2x-5+x) equation: 



28=2(2x-5+x)

We move all terms to the left:

28-(2(2x-5+x))=0

We add all the numbers together, and all the variables

-(2(3x-5))+28=0



We calculate terms in parentheses: -(2(3x-5)), so:

2(3x-5)

We multiply parentheses

6x-10

Back to the equation:

-(6x-10)



We get rid of parentheses

-6x+10+28=0

We add all the numbers together, and all the variables

-6x+38=0

We move all terms containing x to the left, all other terms to the right

-6x=-38

x=-38/-6

x=6+1/3

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