28=2(5v-7)

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Solution for 28=2(5v-7) equation: 



28=2(5v-7)

We move all terms to the left:

28-(2(5v-7))=0



We calculate terms in parentheses: -(2(5v-7)), so:

2(5v-7)

We multiply parentheses

10v-14

Back to the equation:

-(10v-14)



We get rid of parentheses

-10v+14+28=0

We add all the numbers together, and all the variables

-10v+42=0

We move all terms containing v to the left, all other terms to the right

-10v=-42

v=-42/-10

v=4+1/5

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