28=2(5z-4)

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Solution for 28=2(5z-4) equation: 



28=2(5z-4)

We move all terms to the left:

28-(2(5z-4))=0



We calculate terms in parentheses: -(2(5z-4)), so:

2(5z-4)

We multiply parentheses

10z-8

Back to the equation:

-(10z-8)



We get rid of parentheses

-10z+8+28=0

We add all the numbers together, and all the variables

-10z+36=0

We move all terms containing z to the left, all other terms to the right

-10z=-36

z=-36/-10

z=3+3/5

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