28=2(k+2)

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Solution for 28=2(k+2) equation: 



28=2(k+2)

We move all terms to the left:

28-(2(k+2))=0



We calculate terms in parentheses: -(2(k+2)), so:

2(k+2)

We multiply parentheses

2k+4

Back to the equation:

-(2k+4)



We get rid of parentheses

-2k-4+28=0

We add all the numbers together, and all the variables

-2k+24=0

We move all terms containing k to the left, all other terms to the right

-2k=-24

k=-24/-2

k=+12

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