28=2(t+6)

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Solution for 28=2(t+6) equation: 



28=2(t+6)

We move all terms to the left:

28-(2(t+6))=0



We calculate terms in parentheses: -(2(t+6)), so:

2(t+6)

We multiply parentheses

2t+12

Back to the equation:

-(2t+12)



We get rid of parentheses

-2t-12+28=0

We add all the numbers together, and all the variables

-2t+16=0

We move all terms containing t to the left, all other terms to the right

-2t=-16

t=-16/-2

t=+8

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