28=3(2x-3)-3x+6

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Solution for 28=3(2x-3)-3x+6 equation:



28=3(2x-3)-3x+6
We move all terms to the left:
28-(3(2x-3)-3x+6)=0
We calculate terms in parentheses: -(3(2x-3)-3x+6), so:
3(2x-3)-3x+6
We add all the numbers together, and all the variables
-3x+3(2x-3)+6
We multiply parentheses
-3x+6x-9+6
We add all the numbers together, and all the variables
3x-3
Back to the equation:
-(3x-3)
We get rid of parentheses
-3x+3+28=0
We add all the numbers together, and all the variables
-3x+31=0
We move all terms containing x to the left, all other terms to the right
-3x=-31
x=-31/-3
x=10+1/3

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