28=3(v-4)+7v

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Solution for 28=3(v-4)+7v equation: 



28=3(v-4)+7v

We move all terms to the left:

28-(3(v-4)+7v)=0



We calculate terms in parentheses: -(3(v-4)+7v), so:

3(v-4)+7v

We add all the numbers together, and all the variables

7v+3(v-4)

We multiply parentheses

7v+3v-12

We add all the numbers together, and all the variables

10v-12

Back to the equation:

-(10v-12)



We get rid of parentheses

-10v+12+28=0

We add all the numbers together, and all the variables

-10v+40=0

We move all terms containing v to the left, all other terms to the right

-10v=-40

v=-40/-10

v=+4

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