28=4(5f+2)

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Solution for 28=4(5f+2) equation: 



28=4(5f+2)

We move all terms to the left:

28-(4(5f+2))=0



We calculate terms in parentheses: -(4(5f+2)), so:

4(5f+2)

We multiply parentheses

20f+8

Back to the equation:

-(20f+8)



We get rid of parentheses

-20f-8+28=0

We add all the numbers together, and all the variables

-20f+20=0

We move all terms containing f to the left, all other terms to the right

-20f=-20

f=-20/-20

f=1

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