28=4(k-2)

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Solution for 28=4(k-2) equation: 



28=4(k-2)

We move all terms to the left:

28-(4(k-2))=0



We calculate terms in parentheses: -(4(k-2)), so:

4(k-2)

We multiply parentheses

4k-8

Back to the equation:

-(4k-8)



We get rid of parentheses

-4k+8+28=0

We add all the numbers together, and all the variables

-4k+36=0

We move all terms containing k to the left, all other terms to the right

-4k=-36

k=-36/-4

k=+9

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