28=4(k-2)

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Solution for 28=4(k-2) equation:



28=4(k-2)
We move all terms to the left:
28-(4(k-2))=0
We calculate terms in parentheses: -(4(k-2)), so:
4(k-2)
We multiply parentheses
4k-8
Back to the equation:
-(4k-8)
We get rid of parentheses
-4k+8+28=0
We add all the numbers together, and all the variables
-4k+36=0
We move all terms containing k to the left, all other terms to the right
-4k=-36
k=-36/-4
k=+9

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