28=4(k-3)

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Solution for 28=4(k-3) equation: 



28=4(k-3)

We move all terms to the left:

28-(4(k-3))=0



We calculate terms in parentheses: -(4(k-3)), so:

4(k-3)

We multiply parentheses

4k-12

Back to the equation:

-(4k-12)



We get rid of parentheses

-4k+12+28=0

We add all the numbers together, and all the variables

-4k+40=0

We move all terms containing k to the left, all other terms to the right

-4k=-40

k=-40/-4

k=+10

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