28=4(v-2)+2v

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Solution for 28=4(v-2)+2v equation:



28=4(v-2)+2v
We move all terms to the left:
28-(4(v-2)+2v)=0
We calculate terms in parentheses: -(4(v-2)+2v), so:
4(v-2)+2v
We add all the numbers together, and all the variables
2v+4(v-2)
We multiply parentheses
2v+4v-8
We add all the numbers together, and all the variables
6v-8
Back to the equation:
-(6v-8)
We get rid of parentheses
-6v+8+28=0
We add all the numbers together, and all the variables
-6v+36=0
We move all terms containing v to the left, all other terms to the right
-6v=-36
v=-36/-6
v=+6

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