28=4(v-2)+5v

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Solution for 28=4(v-2)+5v equation: 



28=4(v-2)+5v

We move all terms to the left:

28-(4(v-2)+5v)=0



We calculate terms in parentheses: -(4(v-2)+5v), so:

4(v-2)+5v

We add all the numbers together, and all the variables

5v+4(v-2)

We multiply parentheses

5v+4v-8

We add all the numbers together, and all the variables

9v-8

Back to the equation:

-(9v-8)



We get rid of parentheses

-9v+8+28=0

We add all the numbers together, and all the variables

-9v+36=0

We move all terms containing v to the left, all other terms to the right

-9v=-36

v=-36/-9

v=+4

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