28=4+2(n-5)

Solution for 28=4+2(n-5) equation:

28=4+2(n-5)

We move all terms to the left:

28-(4+2(n-5))=0


We calculate terms in parentheses: -(4+2(n-5)), so:

4+2(n-5)

determiningTheFunctionDomain
2(n-5)+4

We multiply parentheses

2n-10+4

We add all the numbers together, and all the variables

2n-6

Back to the equation:

-(2n-6)


We get rid of parentheses

-2n+6+28=0

We add all the numbers together, and all the variables

-2n+34=0

We move all terms containing n to the left, all other terms to the right

-2n=-34

n=-34/-2

n=+17