28=4+3(t+2)

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Solution for 28=4+3(t+2) equation:



28=4+3(t+2)
We move all terms to the left:
28-(4+3(t+2))=0
We calculate terms in parentheses: -(4+3(t+2)), so:
4+3(t+2)
determiningTheFunctionDomain 3(t+2)+4
We multiply parentheses
3t+6+4
We add all the numbers together, and all the variables
3t+10
Back to the equation:
-(3t+10)
We get rid of parentheses
-3t-10+28=0
We add all the numbers together, and all the variables
-3t+18=0
We move all terms containing t to the left, all other terms to the right
-3t=-18
t=-18/-3
t=+6

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