28=4+3(t-5)

Solution for 28=4+3(t-5) equation:

28=4+3(t-5)

We move all terms to the left:

28-(4+3(t-5))=0


We calculate terms in parentheses: -(4+3(t-5)), so:

4+3(t-5)

determiningTheFunctionDomain
3(t-5)+4

We multiply parentheses

3t-15+4

We add all the numbers together, and all the variables

3t-11

Back to the equation:

-(3t-11)


We get rid of parentheses

-3t+11+28=0

We add all the numbers together, and all the variables

-3t+39=0

We move all terms containing t to the left, all other terms to the right

-3t=-39

t=-39/-3

t=+13