28=4v+8(v+5)

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Solution for 28=4v+8(v+5) equation: 



28=4v+8(v+5)

We move all terms to the left:

28-(4v+8(v+5))=0



We calculate terms in parentheses: -(4v+8(v+5)), so:

4v+8(v+5)

We multiply parentheses

4v+8v+40

We add all the numbers together, and all the variables

12v+40

Back to the equation:

-(12v+40)



We get rid of parentheses

-12v-40+28=0

We add all the numbers together, and all the variables

-12v-12=0

We move all terms containing v to the left, all other terms to the right

-12v=12

v=12/-12

v=-1

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