28=5(1+v)-(1-3v)

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Solution for 28=5(1+v)-(1-3v) equation: 



28=5(1+v)-(1-3v)

We move all terms to the left:

28-(5(1+v)-(1-3v))=0

We add all the numbers together, and all the variables

-(5(v+1)-(-3v+1))+28=0



We calculate terms in parentheses: -(5(v+1)-(-3v+1)), so:

5(v+1)-(-3v+1)

We multiply parentheses

5v-(-3v+1)+5

We get rid of parentheses

5v+3v-1+5

We add all the numbers together, and all the variables

8v+4

Back to the equation:

-(8v+4)



We get rid of parentheses

-8v-4+28=0

We add all the numbers together, and all the variables

-8v+24=0

We move all terms containing v to the left, all other terms to the right

-8v=-24

v=-24/-8

v=+3

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