28=5(2w-2)

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Solution for 28=5(2w-2) equation:



28=5(2w-2)
We move all terms to the left:
28-(5(2w-2))=0
We calculate terms in parentheses: -(5(2w-2)), so:
5(2w-2)
We multiply parentheses
10w-10
Back to the equation:
-(10w-10)
We get rid of parentheses
-10w+10+28=0
We add all the numbers together, and all the variables
-10w+38=0
We move all terms containing w to the left, all other terms to the right
-10w=-38
w=-38/-10
w=3+4/5

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