28=6(x+2)-8x

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Solution for 28=6(x+2)-8x equation: 



28=6(x+2)-8x

We move all terms to the left:

28-(6(x+2)-8x)=0



We calculate terms in parentheses: -(6(x+2)-8x), so:

6(x+2)-8x

We add all the numbers together, and all the variables

-8x+6(x+2)

We multiply parentheses

-8x+6x+12

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We get rid of parentheses

2x-12+28=0

We add all the numbers together, and all the variables

2x+16=0

We move all terms containing x to the left, all other terms to the right

2x=-16

x=-16/2

x=-8

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