28=6u-12+2u

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Solution for 28=6u-12+2u equation: 



28=6u-12+2u

We move all terms to the left:

28-(6u-12+2u)=0

We add all the numbers together, and all the variables

-(8u-12)+28=0

We get rid of parentheses

-8u+12+28=0

We add all the numbers together, and all the variables

-8u+40=0

We move all terms containing u to the left, all other terms to the right

-8u=-40

u=-40/-8

u=+5

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