28=7(5y-)

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Solution for 28=7(5y-) equation: 



28=7(5y-)

We move all terms to the left:

28-(7(5y-))=0

We add all the numbers together, and all the variables

-(7(+5y))+28=0



We calculate terms in parentheses: -(7(+5y)), so:

7(+5y)

We multiply parentheses

35y

Back to the equation:

-(35y)



We move all terms containing y to the left, all other terms to the right

-35y=-28

y=-28/-35

y=4/5

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