28=7-(3/2)t

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Solution for 28=7-(3/2)t equation: 



28=7-(3/2)t

We move all terms to the left:

28-(7-(3/2)t)=0



Domain of the equation: 2)t)!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

-(7-(+3/2)t)+28=0

We multiply all the terms by the denominator


-(7-(+3+28*2)t)=0



We calculate terms in parentheses: -(7-(+3+28*2)t), so:

7-(+3+28*2)t

determiningTheFunctionDomain
-(+3+28*2)t+7

We add all the numbers together, and all the variables

-59t+7

Back to the equation:

-(-59t+7)



We get rid of parentheses

59t-7=0

We move all terms containing t to the left, all other terms to the right

59t=7

t=7/59

t=7/59

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