28=8(y-4)+7y

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Solution for 28=8(y-4)+7y equation: 



28=8(y-4)+7y

We move all terms to the left:

28-(8(y-4)+7y)=0



We calculate terms in parentheses: -(8(y-4)+7y), so:

8(y-4)+7y

We add all the numbers together, and all the variables

7y+8(y-4)

We multiply parentheses

7y+8y-32

We add all the numbers together, and all the variables

15y-32

Back to the equation:

-(15y-32)



We get rid of parentheses

-15y+32+28=0

We add all the numbers together, and all the variables

-15y+60=0

We move all terms containing y to the left, all other terms to the right

-15y=-60

y=-60/-15

y=+4

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