28=8c-12

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Solution for 28=8c-12 equation: 



28=8c-12

We move all terms to the left:

28-(8c-12)=0

We get rid of parentheses

-8c+12+28=0

We add all the numbers together, and all the variables

-8c+40=0

We move all terms containing c to the left, all other terms to the right

-8c=-40

c=-40/-8

c=+5

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