28=m+(2m-2)

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Solution for 28=m+(2m-2) equation: 



28=m+(2m-2)

We move all terms to the left:

28-(m+(2m-2))=0



We calculate terms in parentheses: -(m+(2m-2)), so:

m+(2m-2)

We get rid of parentheses

m+2m-2

We add all the numbers together, and all the variables

3m-2

Back to the equation:

-(3m-2)



We get rid of parentheses

-3m+2+28=0

We add all the numbers together, and all the variables

-3m+30=0

We move all terms containing m to the left, all other terms to the right

-3m=-30

m=-30/-3

m=+10

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