28=z-7=12

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Solution for 28=z-7=12 equation: 



28=z-7=12

We move all terms to the left:

28-(z-7)=0

We get rid of parentheses

-z+7+28=0

We add all the numbers together, and all the variables

-1z+35=0

We move all terms containing z to the left, all other terms to the right

-z=-35

z=-35/-1

z=+35

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