28=z/7=12

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Solution for 28=z/7=12 equation: 



28=z/7=12

We move all terms to the left:

28-(z/7)=0

We add all the numbers together, and all the variables

-(+z/7)+28=0

We get rid of parentheses

-z/7+28=0

We multiply all the terms by the denominator


-z+28*7=0

We add all the numbers together, and all the variables

-1z+196=0

We move all terms containing z to the left, all other terms to the right

-z=-196

z=-196/-1

z=+196

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