28b=-29(3b+1=2

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Solution for 28b=-29(3b+1=2 equation: 



28b=-29(3b+1=2

We move all terms to the left:

28b-(-29(3b+1)=0



We calculate terms in parentheses: -(-29(3b+1), so:

-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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-29(3b+1





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