28x+6=10x2

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Solution for 28x+6=10x2 equation:



28x+6=10x^2
We move all terms to the left:
28x+6-(10x^2)=0
determiningTheFunctionDomain -10x^2+28x+6=0
a = -10; b = 28; c = +6;
Δ = b2-4ac
Δ = 282-4·(-10)·6
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-32}{2*-10}=\frac{-60}{-20} =+3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+32}{2*-10}=\frac{4}{-20} =-1/5 $

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