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28x+88x+48=6x-7x^2
We move all terms to the left:
28x+88x+48-(6x-7x^2)=0
We add all the numbers together, and all the variables
-(6x-7x^2)+116x+48=0
We get rid of parentheses
7x^2-6x+116x+48=0
We add all the numbers together, and all the variables
7x^2+110x+48=0
a = 7; b = 110; c = +48;
Δ = b2-4ac
Δ = 1102-4·7·48
Δ = 10756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10756}=\sqrt{4*2689}=\sqrt{4}*\sqrt{2689}=2\sqrt{2689}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-2\sqrt{2689}}{2*7}=\frac{-110-2\sqrt{2689}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+2\sqrt{2689}}{2*7}=\frac{-110+2\sqrt{2689}}{14} $
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