28x-10-12x=4(4x-3)+2

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Solution for 28x-10-12x=4(4x-3)+2 equation:


Simplifying
28x + -10 + -12x = 4(4x + -3) + 2

Reorder the terms:
-10 + 28x + -12x = 4(4x + -3) + 2

Combine like terms: 28x + -12x = 16x
-10 + 16x = 4(4x + -3) + 2

Reorder the terms:
-10 + 16x = 4(-3 + 4x) + 2
-10 + 16x = (-3 * 4 + 4x * 4) + 2
-10 + 16x = (-12 + 16x) + 2

Reorder the terms:
-10 + 16x = -12 + 2 + 16x

Combine like terms: -12 + 2 = -10
-10 + 16x = -10 + 16x

Add '10' to each side of the equation.
-10 + 10 + 16x = -10 + 10 + 16x

Combine like terms: -10 + 10 = 0
0 + 16x = -10 + 10 + 16x
16x = -10 + 10 + 16x

Combine like terms: -10 + 10 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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